# 生成器：自定义的迭代器对象 def fn():     print(1)     yield 666     print(2)     yield 888     print(3) # print(fn()) """ obj = fn()  # generator object => [666, 888] print(obj) # 去生成器中执行代码，拿到遇到的第一个yield后面的值，并停止运行 print(obj.__next__()) # 再接着上一个yield，再进行往下执行代码，再拿到下一个个yield后面的值，并停止运行 print(obj.__next__()) # 重复上面的过程，如果没有遇到yield，就报错 print(obj.__next__()) """ for v in [666, 888]:     print(v) print('--------------------') # 将传入的值扩大两倍返回 # def fn1(a, b, c): #     yield a * 2 #     yield b * 2 #     yield c * 2 # # for v in fn1(10, 20, 30): #     print(v) # 解决方案 # def fn1(*args): #     i = 0 #     while i < len(args): #         yield args[i] * 2 #         i += 1 # # for v in fn1(10, 20, 30, 40, 50): #     print(v) # 依次获取阶乘 1! 2! 3! ... def fn2():     total = 1     count = 1     while True:         total *= count         yield total         count += 1 obj = fn2() print(obj.__next__()) print(obj.__next__()) print(obj.__next__()) print(obj.__next__()) print(obj.__next__()) print('=================') # 了了解 # def fn3(): #     msg = yield 1 #     print(msg) #     yield 2 # obj3 = fn3() # print(obj3.__next__()) # # 1.send会为当前停止的yield传入参数，内部可以通过yield来接收传入的参数 # # 2.send自身也会调用__next__()去获取下一个yield的结果 # result = obj3.send('ooo') # print(result) def fn4(peoples):     count = 0     print('%s在面试' % peoples[count])     while count < len(peoples):         name = yield peoples[count]         count += 1         print(name + "叫来%s来面试" % peoples[count]) peoples = ['张三', '李四', '王五'] obj4 = fn4(peoples) name = obj4.send(None)  # 第一次没有yield接收值，所以只能调__next__()，或是send(None) print(name + '面试完毕') while True:     try:         name = obj4.send(name)         print(name + '面试完毕')     except Exception:         print('所有人面试完毕')         break